A solution containing 1.1 g NaOH in 325 ml, water is titrated with 444 mL HCL. what is the concentration of HCL in the original solution?

The reaction between NaOH and HCl takes place as shown by the equation;

NaOH (aq) + 2HCl (aq) = NaCl (aq) + H2O (l)

The moles of NaOH that reacted will be given;

= 1.1/40 = 0.0275 Moles

The mole ratio is 1 : 2

Therefore; the number of moles of HCl will be;

= 0.0275 moles * 2 = 0.055 moles

The molarity or concentration of HCl will be;

0.055 / 0.444 = 0.1239 M

Therefore, the concentration of HCl is 0.124 M