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12 November, 14:52

If 38.5 grams of potassium react with excess oxygen gas, how many grams of potassium oxide can be produced? 4K + O2 yields 2K2O

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  1. 12 November, 15:03
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    46.40 g.

    Explanation:

    It is a stichiometric problem. The balanced equation of the reaction: 4K + O₂ → 2K₂O. It is clear that 4.0 moles of K reacts with 1.0 mole of oxygen produces 2.0 moles of K₂O. We should convert the mass of K (38.5 g) into moles using the relation:

    n = mass / molar mass,

    n = (38.5 g) / (39.098 g/mol) = 0.985 mole.

    Using cross multiplication:

    4.0 moles of K produces → 2.0 moles of K₂O, from the stichiometry.

    0.985 mole of K produces →? moles of K₂O.

    ∴ The number of moles of K₂O produced = (0.985 mole) (2.0 mole) / (4.0 mole) = 0.4925 mole ≅ 0.5 mole.

    Now, we can get the mass of K₂O:

    ∴ mass = n x molar mass = (0.5 mole) (94.2 g/mol) = 46.40 g.
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