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1 May, 16:05

50.0 g of copper was dropped into 250.0mL of H2O at 25.0°C in a coffee cup calorimeter. The copper and H2O reached thermal equilibrium at 27.5°C. Calculate the initial temperature of the copper. Specific heat of water is 4.184 J/g°C and specific heat of copper is 0.385 J/g°C.

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  1. 1 May, 16:18
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    Initial temperature of copper = 163.3 °C

    Explanation:

    Specific heat capacity:

    It is the amount of heat required to raise the temperature of one gram of substance by one degree.

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = final temperature - initial temperature

    Given dа ta:

    Mass of copper = 50 g

    Initial temperature of copper = ?

    Final temperature = 27.5°C

    Initial temperature of water = 25.0°C

    Specific heat capacity of copper = 0.385 j/g.°C

    Specific heat capacity of water = 4.184 J/g°C

    Volume of water = 250.0 mL or 250.0 g

    Solution:

    Formula:

    - Qm = + Qw

    Now we will put the values in formula.

    -50 g * 0.385 j/g.°C * [ 27.5°C - x] = 250 g * 4.184 J/g°C * [ 27.5°C - 25.0°C]

    -50 g * 0.385 j/g.°C * [ 27.5°C - x] = 250 g * 4.184 J/g°C * 2.5°C

    -19.25 j/°C * [ 27.5°C - x] = 2615 j

    27.5°C - x = 2615 j / - 19.25 j/°C

    27.5°C - x = - 135.8°C

    x = 27.5°C + 135.8°C

    x = 163.3 °C
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