Ask Question
8 December, 17:42

2.15 g of an unknown gas at 71 degrees C and 1.10 atm is stored in a 1.75 L flask.

What is the density of the gas?

What is the molar mass of the gas?

+2
Answers (1)
  1. 8 December, 17:44
    0
    Applying gas law:

    PV=nRT

    n/V = (1.10 atm) / ((0.08205746 L atm/K mol) x (71 + 273) K) = 0.0389 mol/L

    density:

    (1.10 g) / (1.75 L) = 0.628 g/L

    molar mass:

    (0.628 g/L) / (0.0389 mol/L) = 16.14 g/mol

    its molar mass is nearly equal to NH3 that is 17.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “2.15 g of an unknown gas at 71 degrees C and 1.10 atm is stored in a 1.75 L flask. What is the density of the gas? What is the molar mass ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers