Calculate the molarity (m) of a solution prepared by dissolving 10.7 g nai in 0.250 l.

Molarity is defined as the number of moles of solute in 1 L of solution

number of moles of NaI - 10.7 g / 150 g/mol = 0.0713 mol

there are 0.0713 mol in 0.250 L

we need to find the number of NaI moles in 1 L

if 0.250 L contains - 0.0713 mol

then 1 L contains - 0.0713 mol / 0.250 L = 0.285 mol/L

molarity is 0.285 M