A gas at a fixed volume had a temperature change from 87.00 K to 65.25 K. At 65.25 K, the pressure was recorded as 18 Pa. What was the initial pressure?

Question

Macy

Chemistry

26 June, 07:33

A gas at a fixed volume had a temperature change from 87.00 K to 65.25 K. At 65.25 K, the pressure was recorded as 18 Pa. What was the initial pressure?

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Answers (1)

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Georgia Vaughn · Answer 1

The initial pressure was 25.2 Pa.

Explanation:

According to the Gay-Lussac's Law, the pressure of given amount of gas is directly proportional to the temperature in kelvin while volume is kept constant.

Formula:

P₁/T₁ = P₂/T₂

P₁ = Initial pressure

T₁ = Initial temperature

P₂ = Final pressure

T₂ = Final temperature

Given dа ta:

T₁ = 87 K

T₂ = 62.25 K

P₂ = 18 Pa

P₁ = ?

Now we will put the values in formula,

P₁/T₁ = P₂/T₂

P₁ = P₂/T₂*T₁

P₁ = (18 Pa / 62.25 K) * 87 K

P₁ = 0.2892 Pa/k * 87 K

P₁ = 25.2 Pa

The initial pressure was 25.2 Pa.