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30 August, 05:27

Find the ph of of 100 ml of an aqueous 0.43m baoh2 solution

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  1. 30 August, 05:52
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    Answer is: pH of barium hydroxide is 13.935.

    Chemical dissociation of barium hydroxide in water:

    Ba (OH) ₂ (aq) → Ba²⁺ (aq) + 2OH⁻ (aq).

    c (Ba (OH) ₂) = 0.43 M.

    V (Ba (OH) ₂) = 100 mL : 1000 mL/L = 0.1 L.

    n (Ba (OH) ₂) = 0.43 mol/L · 0.1 L.

    n (Ba (OH) ₂) = 0.043 mol.

    From chemical reaction: n (Ba (OH) ₂) : n (OH⁻) = 1 : 2.

    n (OH⁻) = 0.086 mol.

    c (OH⁻) = 0.86 mol/L.

    pOH = - logc (OH⁻).

    pOH = 0.065.

    pH = 14 - 0.065 = 13.935.
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