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29 January, 16:13

If 30 g of HCl is reacted with excess NaOH, and 10g of NaCl is produced, what is the percent yield of the experiment?

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  1. 29 January, 16:24
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    Percent yield of NaCl = 20.85%

    Explanation:

    Given dа ta:

    Mass of HCl = 30 g

    Actual yield of NaCl = 10 g

    Percent yield of NaCl = ?

    Solution:

    Chemical equation:

    HCl + NaOH → NaCl + H₂O

    Moles of HCl:

    Number of moles = mass / molar mass

    Number of moles = 30 g / 36.5 g/mol

    Number of moles = 0.82 mol

    Now we will compare the moles of HCl with NaCl

    HCl : NaCl

    1 : 1

    0.82 : 0.82

    Theoretical yield:

    Mass = number of moles * molar mass

    Mass = 0.82 mol * 58.5 g/mol

    Mass = 47.97 g

    Percentage yield:

    Formula:

    Percent yield = Actual yield / theoretical yield * 100

    Now we will put the values.

    Percent yield = 10 g / 47.97 g * 100

    Percent yield = 20.85%
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