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10 October, 00:44

A 0.060 m solution of an acid has a ph of 5.12. calculate the ka of the acid.

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  1. 10 October, 00:56
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    From the equation: pH=.5pC *.5pKa

    pKa = 2*pH/pC2 * (5.12) - (-log (.06)) = 9.018

    ka = 10^-9.018=9.59*10^-10
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