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15 January, 18:40

Aluminum had a specific heat of 0.215 cal / (g °C). When 25.7 cal (108.5 J) of heat is added to 18.4 g of aluminum at 20.0°C, what is the final temperature of the aluminum?

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  1. 15 January, 18:46
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    26.5°C

    Explanation:

    Heat added is the product of mass, specific heat capacity, and change in temperature.

    q = mC (T - T₀)

    25.7 cal = (18.4 g) (0.215 cal/g/°C) (T - 20.0°C)

    T = 26.5°C
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