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17 August, 09:47

What is the final concentration, in mg/mL, for a solution prepared by adding 12.00 mL of a 3.590 mg/mL Cu2 + stock solution into 100.00 mL volumetric flask and filled with water to the calibration mark?

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  1. 17 August, 10:04
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    0.4308 mg/mL

    Explanation:

    Given data

    Initial concentration (C₁) : 3.590 mg/mL Initial volume (V₁) : 12.00 mL Final concentration (C₂) : ? Final volume (V₂) : 100.00 mL

    We can find the final concentration using the dilution rule.

    C₁ * V₁ = C₂ * V₂

    C₂ = C₁ * V₁ / V₂

    C₂ = 3.590 mg/mL * 12.00 mL / 100.00 mL

    C₂ = 0.4308 mg/mL
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