How many joules of heat are lost by 3580 KG granite as it goes from 41.2°C to - 12.9°C

The granite loses 1.53 * 10⁸ J of heat.

The formula for the heat (q) transferred is

q = mCΔT

I shall assume that the specific heat capacity of granite is 0.790 J·°C⁻¹g⁻¹.

m = 3.580 * 10⁶ g; ΔT = T_f - T_i = - 12.9 °C - 41.2 °C = - 54.1 °C

∴ q = 3.580 * 10⁶ g * 0.790 J·°C⁻¹g⁻¹ * (-54.1 °C) = - 1.53 * 10⁸ J

The granite block loses 1.53 * 10⁸ J.