The henry's law constant (k) for carbon monoxide in water at 25°c is 9.71 * 10-4 mol / (l·atm). how many grams of co will dissolve in 1.00 l of water if the partial pressure of co is 2.75 atm?

Question

Howie

Chemistry

8 December, 02:59

The henry's law constant (k) for carbon monoxide in water at 25°c is 9.71 * 10-4 mol / (l·atm). how many grams of co will dissolve in 1.00 l of water if the partial pressure of co is 2.75 atm?

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Sonia Weiss · Answer 1

In this question, you are given the Henry constant (9.71 * 10-4 mol/l atm), the volume (1 l) and the pressure (2.75 atm). The molecular mass of CO should be 28g/mol.

Then the amount of carbon monoxide in the water in grams should be: 9.71 * 10-4 mol/l atm * 1l * 2.75atm * 28g/mol = 747.67 * 10^-4 = 0.074767 grams