What is the kw of pure water at 50.0°c, if the ph is 6.630? 5.50 * 10-14 2.13 * 10-14 1.00 * 10-14 2.34 * 10-7 there is not enough information to calculate the kw?

Question

Mauricio

Chemistry

6 November, 13:10

What is the kw of pure water at 50.0°c, if the ph is 6.630? 5.50 * 10-14 2.13 * 10-14 1.00 * 10-14 2.34 * 10-7 there is not enough information to calculate the kw?

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Larry Lynn · Answer 1

Answer is: Kw of pure water at 50.0°C is 5.50 * 10-14.

pH = 6.630.

pH = - log [H⁺].

[H⁺] = 10∧ (-pH).

[H⁺] = 10∧ (-6.63) = 2.34·10⁻⁷ M.

[H⁺] · [OH⁻] = x.

Kw = ?.

Kw = [H ⁺] · [OH⁻].

Kw = x².

Kw = (2.34·10⁻⁷ M) ².

Kw = 5.50·10⁻¹⁴ M².

Kw is ionic product of water.