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10 December, 02:18

How much 0.02 m kmno4 solution should be needed if the solutions tested have a composition of 3% h2o2 by mass?

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  1. 10 December, 02:24
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    When the concentration is expressed in mass percentage, that means there is 3 g of solvent H₂O₂ in 100 grams of the solution. Then, that means the remaining amount of solute is 97 g. We use the value of molarity (moles/liters) to determine the amount of solution in liters, denoted as V. The solution is as follows:

    0.02 mol KMnO4/L solution * 158.034 g KMnO4/mol * V = 97 g KMnO4

    Solving for V,

    V = 30.69 L
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