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19 February, 20:26

How many liters of water can be produced from 5.0 liters of butane gas at STP, assuming excess oxygen?

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  1. 19 February, 20:43
    0
    25 L of H₂O

    Solution:

    The balanced chemical equation is as,

    2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

    As at STP one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,

    44.8 L (2 mol) C₄H₁₀ produces = 224 L (10 mol) of H₂O

    So,

    5.0 L of C₄H₁₀ will produce = X L of H₂O

    Solving for X,

    X = (5.0 L * 224 L) : 44.8 L

    X = 25 L of H₂O
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