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6 May, 21:23

If 0.78% of a radioactive substance remains, then how many half-lives have passed?

3

7

6

4

+4
Answers (1)
  1. 6 May, 21:52
    0
    The answer would be 7 because of this solution:

    You divide (1|2) and then divide it by 7.

    The answer should be 0.78% of the remaining half-lives after 7. Because of the remaining radioactive substance that happens during that 0.78 percentage.
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