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12 December, 22:49

What is the mass of calcium in 2.3•10^23 molecules of calcium phosphate

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  1. 12 December, 23:19
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    N (Ca) = 3*N (Ca₃ (PO₄) ₂) =

    =3*2.3*10²³=6.9*10²³

    6.02*10²³→40g

    6.9*10²³→Xg

    m (Ca) = X≈45.85g
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