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23 May, 14:45

Calculate the morality of each of the following solutions: a. 15.4 g KCl in 289.2 mL solution b. 14.4 g of CaCl2 in 0.614 L solution c. 28.0 mL of 3.00 M H2SO4 diluted to 0.250 L

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  1. 23 May, 14:52
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    The answer is:

    a. 0.712 M

    b. 0.210 M

    c. 0.336 M

    Molarity is a measure of the concentration of solute in a solution.

    It can be expressed as moles of solute : volume of solution:

    c = n : V

    where:

    c - concentration of solute,

    n - moles of solute

    V - volume of solution

    n can be expressed as:

    n = m : Mr

    where:

    n - moles of solute

    m - mass of solute

    Mr - relative molecular mass

    a. We know volume:

    V = 289.2 mL = 0.2892 L

    We need n and c.

    n = m : Mr

    m = 15.4 g

    Mr (KCl) = 74.55 g/mol

    n = 15.4 g : 74.55 g/mol

    n = 0.206 mol

    Thus,

    c = 0.206 mol : 0.2892 L

    c = 0.712 mol/L = 0.712 M

    b. We know volume:

    V = 0.614 L

    We need n and c.

    n = m : Mr

    m = 14.4 g

    Mr (CaCl₂) = 110.98 g/mol

    n = 14.4 g : 110.98 g/mol

    n = 0.129 mol

    Thus,

    c = 0.129 mol : 0.614 L

    c = 0.210 mol/L = 0.210 M

    c. We can use formula:

    m₁V₁ = m₂V₂

    m₁ = 3 M

    V₁ = 28 mL = 0.028 L

    m₂ = ?

    V₂ = 0.250 L

    Thus:

    3 M * 0.028 L = m₂ * 0.250 L

    m₂ = 0.336 M
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