How many moles of sucrose (C12H22O11) would be in 8.7 L of a 1.1 M solution of sucrose?

Question

Chasity Carson

Chemistry

18 October, 15:17

How many moles of sucrose (C12H22O11) would be in 8.7 L of a 1.1 M solution of sucrose?

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Answers (1)

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Burnett · Answer 1

9.57 mol.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute) / (V of the solution (L)).

∴ M = (no. of moles of sucrose) / (V of the solution (L)).

1.1 M = (no. of moles of sucrose) / (8.7 L).

∴ no. of moles of sucrose = (1.1 M) (8.7 L) = 9.57 mol.