How many grams of NO will be produced from 60.0g of NO2 reacted with excess water in the following chemical reaction?

3NO2 (g) + H2O (l) - -> 2HNO3 (g) + NO (g)

Mass = 19.78 g

Explanation:

Given dа ta:

Mass of NO produced = ?

Mass of NO₂ reacted = 60.0 g

Solution:

Chemical equation:

3NO₂ (g) + H₂O (l) → 2HNO₃ (g) + NO (g)

Number of moles of NO₂:

Number of moles = mass/molar mass

Number of moles = 60.0 g / 46 g/mol

Number of moles = 1.3 mol

Now we will compare the moles of NO₂ with NO.

NO₂ : NO

3 : 1

1.3 : 1/3*1.3 = 0.43 mol

Mass of NO:

Mass = number of moles * molar mass

Mass = 0.43 mol * 46 g/mol

Mass = 19.78 g