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7 November, 11:54

When 8.00 * 1022 molecules of ammonia react with 7.00 * 1022 molecules of oxygen according to the chemical equation shown below, how many grams of nitrogen gas are produced?

4 NH3 (g) + 3 O2 (g) → 2 N2 (g) + 6 H2O (g)

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  1. 7 November, 12:04
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    According to the equation: 4 moles of NH3 requires 3 moles of Oxygen

    1 mole = 6.02 x 10^23

    X moles = 8 x 10^22

    X=0.13 moles of NH3

    and for Oxygen

    X = (7x10^22) / (6.02x10^23)

    X=0.116 of Oxygen therefore Ammonia is the limiting factor.

    4 moles NH3: 2 moles N2

    0.13 moles: X

    X=0.065 moles of Nitrogen gas will be formed.
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