For the process 2SO2 (g) + O2 (g) 2SO3 (g), S = - 187.9 J/K and H = - 198.4 kJ at 297.0 K are known. What is the entropy of this reaction? Use G = H - TS.

A) - 386.3 J/K

B) - 198.4 kJ/K

C) - 187.9 J/K

D) - 139.3 kJ

Question

Raven Moore

Chemistry

26 August, 19:19

For the process 2SO2 (g) + O2 (g) 2SO3 (g), S = - 187.9 J/K and H = - 198.4 kJ at 297.0 K are known. What is the entropy of this reaction? Use G = H - TS.

A) - 386.3 J/K

B) - 198.4 kJ/K

C) - 187.9 J/K

D) - 139.3 kJ

+5

Answers (1)

Know the Answer?

Allyson Walker · Answer 1

The process is

2SO₂ (g) + O₂ (g) → 2SO₃ (g)

According to Gibs free energy equation, G = H - TS

where G = Gibs free energy which is a measure of chemical energy

H = Enthalpy value of enthalpy given, H = - 198.4 kJ

T = temperature in kelvins = 297 K

S = entropy of this reaction

which is S = - 187.9 J/K

Entopy is already given in the question which is - 187.9 J/k

For the process 2SO2 (g) + O2 (g) 2SO3 (g), S = - 187.9 J/K and H = - 198.4 kJ at 297.0 K are known. What is the entropy of this reaction? Use G = H - TS.A) - 386.3 J/KB) - 198.4 kJ/KC) - 187.9 J/KD) - 139.3 kJ

For the process 2SO2 (g) + O2 (g) 2SO3 (g), S = - 187.9 J/K and H = - 198.4 kJ at 297.0 K are known. What is the entropy of this reaction? Use G = H - TS.

A) - 386.3 J/K

B) - 198.4 kJ/K

C) - 187.9 J/K

D) - 139.3 kJ