How many grams of H2 can be formed from 54.6 grams of NH3 in the following reaction? 2NH3 (g) - -> 3H2 (g) + N2 (g)

9.64g

Explanation:

The balanced equation for the reaction is given below:

2NH3 (g) - > 3H2 (g) + N2 (g)

Next, we need to calculate the mass NH3 that decomposed and the mass of H2 produced from the balanced equation. This is illustrated below:

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 that decomposed from the balanced equation = 2 x 17 = 34g

Molar Mass of H2 = 2x1 = 2g/mol

Mass of H2 produced from the balanced equation = 3 x 2 = 6g.

Now, we can obtain the mass of H2 formed from 54.6g of NH3 as follow:

From the balanced equation above,

34g of NH3 decomposed to produce 6g of H2.

Therefore, 54.6g of NH3 will decompose to produce = (54.6x6) / 34 = 9.64g of H2

Therefore, 9.64g of H2 can be obtained from 54.6g of NH3.