How much energy must be transferred as heat to the 420 kg of water in a bathtub in order to raise the water temperature from 25 degrees celsius to 37 degrees celsius

Answer: 21,072.24KJ

Explanation:

increasing the temperature of 420 kg of water from 25 degrees C to 37degrees C. The change in temperature is ∆T = (37 - 25) degrees C = 12 degrees C.

The specific heat capacity of water is 4,181 J / kg degree C, so the equation gives:

Q=mC ∆T

Q = 420 kg * 4181 J / kg degree C * 12 degrees C

=21, 072,240 J = 21,072.24 kJ