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8 June, 09:16

What are the [H+] and [OH-] for a substance with a ph of 9.2?

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Answers (1)
  1. 8 June, 09:28
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    The answer to your question is [H⁺] = 6.31 x 10⁻¹⁰ M [OH⁻] = 1.58 x 10⁻⁵ M

    Explanation:

    Data

    [H⁺] = ?

    [OH⁻] = ?

    pH = 9.2

    Process

    To find the answer to this question we must start by using the formula of pH and simplify to find the [H⁺] then calculate the pOH to find the [OH⁻]

    1. - Write the formula of pH

    pH = - log [H⁺]

    2. - Find the [H⁺]

    9.2 = - log[H⁺]

    -Solve for [H⁺]

    [H⁺] = antilog (-9.2)

    -Result

    [H⁺] = 6.31 x 10⁻¹⁰ M

    3. - Calculate the pOH

    pH + pOH = 14

    -Solve for pOH

    pOH = 14 - 9.2

    -Result

    pOH = 4.8

    4. - Calculate the [OH⁻]

    -Substitution

    4.8 = - log [OH⁻]

    -Solve for [OH⁻]

    [OH⁻] = antilog (-4.8)

    -result

    [OH⁻] = 1.58 x 10⁻⁵ M
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