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18 July, 08:01

At what temperature will a balloon have a volume of 6.08 L if the temperature is 41.0 ℃ when its volume is 4.87 L? in kelvin

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  1. 18 July, 08:20
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    T₂ = 251.6 K

    Explanation:

    Given dа ta:

    Initial temperature = 41°C

    Initial volume = 4.87 L

    Final volume = 6.08 L

    Final temperature = ?

    Solution:

    Initial temperature = 41°C (41+273.15 = 314.15 K)

    The given problem will be solve through the Charles Law.

    According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

    Mathematical expression:

    V₁/T₁ = V₂/T₂

    V₁ = Initial volume

    T₁ = Initial temperature

    V₂ = Final volume

    T₂ = Final temperature

    Now we will put the values in formula.

    V₁/T₁ = V₂/T₂

    T₂ = V₂T₁ / V₁

    T₂ = 4.87 L * 314.15 K / 6.08 L

    T₂ = 1529.9 L. K / 6.08 L

    T₂ = 251.6 K
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