Ask Question
8 June, 04:15

A compound contains sulfur, oxygen, and chlorine. Analysis shows that it contains by mass 26.95% sulfur and 59.61% chlorine. What is the simplest formula for this compound?

+5
Answers (2)
  1. 8 June, 04:16
    0
    SCl₂

    Explanation:

    In order to know the empirical formula, we have to follow a series of steps.

    Step 1: Divide each percentage by the atomic mass

    S: 26.95/32.07 = 0.8403

    Cl: 59.61/35.45 = 1.682

    Step 2: Divide all the numbers by the smallest one.

    S: 0.8403/0.8403 = 1

    Cl: 1.682/0.8403 ≈ 2

    The empirical formula of the compound is SCl₂.
  2. 8 June, 04:26
    0
    The empirical formula = the simplest formula of this compound is SOCl2

    Explanation:

    Step 1: Data given

    Suppose the mass of the compound is 100 grams

    The compound contains:

    ⇒ 26.95 % sulfur = 26.95 grams

    ⇒ 59.61 % chlorine = 59.61 grams

    ⇒ 100 - 26.95 - 59.61 = 13.44 % oxygen = 13.44 grams

    Molar mass of sulfur = 32.065 g/mol

    Molar mass of oxygen = 16 g/mol

    Molar mass of chlorine = 35.45 g/mol

    Step 2: Calculate moles

    Moles = mass / molar mass

    Moles Sulfur = 26.95 grams / 32.065 g/mol = 0.8405 moles

    Moles chlorine = 59.61 grams / 35.45 g/mol = 1.682 moles

    Moles oxygen = 13.44 grams / 16 g/mol = 0.84 moles

    Step 3: Calculate mol ratio

    We divide by the smallest amount of moles

    S: 0.8405/0.84 = 1

    Cl = 1.682 / 0.84 = 2

    O = 0.84 / 0.84 = 1

    The empirical formula = the simplest formula of this compound is SOCl2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A compound contains sulfur, oxygen, and chlorine. Analysis shows that it contains by mass 26.95% sulfur and 59.61% chlorine. What is the ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers