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14 June, 13:57

A sample of hydrated copper (II) sulfate has a mass of 4.56 g. After heating, it has a mass of 2.92 g.

What is the percent by mass of water in the hydrate?

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  1. 14 June, 14:06
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    36.0%.

    Explanation:

    The mass of water = mass of hydrated copper (II) sulfate - mass of copper (II) sulfate after heating = 4.56 g - 2.92 g = 1.64 g.

    The percent by mass of water in the hydrate = (mass of water/mass of hydrated copper (II) sulfate) * 100 = (1.64 g/4.56 g) * 100 = 35.96% ≅ 36.0%.
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