What is the volume occupied by 11.0 grams of a gas at STP if the molecular mass of the gas is 44.0?

We can use the ideal gas law equation to find the volume occupied by the gas

PV = nRTwhere

P - standard pressure - 101 325 Pa

V - volume

n - number of moles - 11.0 g / 44 g/mol = 0.25 mol

R - universal gas constant - 8.314 Jmol⁻¹K⁻¹

T - standard temperature - 273 K

substituting the values in the equation

101 325 Pa x V = 0.25 mol x 8.314 Jmol⁻¹K⁻¹ x 273 K

V = 5.60 L

volume of the gas is 5.60 L