A pure titanium cube has an edge length of 2.84 in how many titanium atoms does it contain? titanium has a density of 4.50g/cm3.

First let us assume that the shape of the Titanium is a perfect square so that the volume is calculated as:

V = s^3

V = (2.84 in) ^3

V = 22.91 in^3

Then calculate for the mass:

m = (4.50 g/cm^3) * 22.91 in^3 * (2.54 cm/1in) ^3

m = 1,689.15 g

Calculating for the number of atoms by dividing with molar mass (47.87g/mol) and multiplying with Avogadros number:

atoms = [ (1,689.15 g) / (47.87g/mol) ] * (6.022 x 10^23 atoms/mol)

atoms = 2.125 x 10^25 atoms