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3 November, 10:50

If the standard solutions had unknowingly been made up to be 0.0024 m agno3 and 0.0040 m k2cro4, would this have affected your results? how?

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  1. 3 November, 11:19
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    2AgNO3+K2CrO4⇒Ag2CrO4 (s) + 2KNO3

    Hence by mixing 0.0024M AgNO3 and 0.004M

    K2CrO4, we will have Ag2CrO4 which is precipitated out and leave us with

    0.0024M KN03 which is mixed with (0.004-0.0024/2) M, it can be 0.0028M, of K2Cr04
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