How many grams of NaOH are produced from 1.20 x 10^2 of Na2O

Write an balance the equation

Na2O + H2O - > 2 NaOH

Calculate the molecular mass of Na2O and NaOH from the atomic mass from the periodic table.

Na = 23

O=16

H=1

Na2O = 23 * 2 + 16 = 62

NaOH = 23+16+1 = 40

For the stoichiometry of the reaction one mole of Na2O = 62g produce two mol of NaOH = 2 * 40 = 80 g

120 g Na2O x 80g NaOH / 62g Na2O=

154.8 g NaOH