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23 December, 08:59

A flexible container at an initial volume of 6.13 L contains 6.51 mol of gas. More gas is then added to the container until it reaches a final volume of 13.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

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  1. 23 December, 09:06
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    7.61 moles

    Explanation:

    Hello, we'll first of all get the required data from the question to enable us find the best approach to the question.

    Data;

    Initial volume (V1) = 6.13L

    Initial number of moles (n1) = 6.51mol

    Final volume (V2) = 13.3L

    Final number of moles = ?

    To solve this question, we'll use Avogadro's law which states that the number of moles of a fixed mass of gas is directly proportional to its volume provided that temperature and pressure remains constant.

    Mathematically,

    n = kV, k = n / V

    n1 / V1 = n2 / V2 = n3 / V3 = ... = Nx / Vx

    n1 / V1 = n2 / V2

    Substitute the values into the above equation

    6.51 / 6.13 = n2 / 13.3

    n2 = (6.51 * 13.3) / 6.13

    n2 = 14.12moles

    The final mole of the gas is equal to 14.12mol

    To find the number of moles added to the system, we'll subtract the initial mole from the final mole.

    Number of moles added = n2 - n1

    Number of moles added = 14.12 - 6.51

    Number of moles added = 7.61moles

    Therefore, 7.61 moles of the gas was added into the system
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