Give the percent yield when 28.16 g of co2 are formed from the reaction of 8.000 moles of c8h18 with 4.000 moles of o2. 2 c8h18 + 25 o2 → 16 co2 + 18 h2o

Question

Mckayla Villa

Chemistry

2 February, 23:00

Give the percent yield when 28.16 g of co2 are formed from the reaction of 8.000 moles of c8h18 with 4.000 moles of o2. 2 c8h18 + 25 o2 → 16 co2 + 18 h2o

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Eve Ford · Answer 1

equal moles of C8H18 and O2 are reacted to give equal no. of moles of CO2.

mole ratio of C8H18 = (1/2) x 8 = 4 moles

mole ratio of O2 = (1/25) x 4 = 0.16 moles

so, limiting reagent is O2

the no. of moles of CO2 formed = 16 x 0.16 = 2.56 moles

weight of CO2 formed (theoretical weight) = 2.56 x 44 = 112.64

Percentage yield = (practical yiel/theoretical yield) x 100 = (28.16/112.64) x100 = 25%