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27 July, 17:21

If 21 mL of gas is subjected to a temperature change from 10.0°C to 120°C and a pressure change from 1.0 atm to 15 atm, the new volume is: (Be sure to use the correct number of significant figures.) 1.9 mL 1.0 mL 0.53 mL 440 mL

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  1. 27 July, 17:47
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    The new volume is 1.9 ml

    calculation

    The new volume is calculated using the combined gas equation

    that is P1V1/T1 = P2V2/T2 where

    P1 = 1.0 atm

    V1 = 21 ml

    T1 = 10.0 c into kelvin = 10 + 273 = 283 k

    P2 = 15 atm

    V2=? Ml

    T2 = 120 c into kelvin = 120 + 273 = 393 K

    make V2 the subject of the formula by multiplying both side by T2/P2

    V2=T2P1v1 / P2T1

    V2=[ (393 k x 1.0 atm x 21 ml) / (15 atm x 283 K) ] = 1.9 Ml
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