If 21 mL of gas is subjected to a temperature change from 10.0°C to 120°C and a pressure change from 1.0 atm to 15 atm, the new volume is: (Be sure to use the correct number of significant figures.) 1.9 mL 1.0 mL 0.53 mL 440 mL

The new volume is 1.9 ml

calculation

The new volume is calculated using the combined gas equation

that is P1V1/T1 = P2V2/T2 where

P1 = 1.0 atm

V1 = 21 ml

T1 = 10.0 c into kelvin = 10 + 273 = 283 k

P2 = 15 atm

V2=? Ml

T2 = 120 c into kelvin = 120 + 273 = 393 K

make V2 the subject of the formula by multiplying both side by T2/P2

V2=T2P1v1 / P2T1

V2=[ (393 k x 1.0 atm x 21 ml) / (15 atm x 283 K) ] = 1.9 Ml