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16 September, 17:41

What is the concentration of naoh needed to get a solution with ph 12.25?

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  1. 16 September, 17:46
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    POH = 14-pH = 14-12,25 = 1,75

    pOH = - log[OH-]

    [OH-] = 10^-pOH

    [OH-] = 10^-1,75

    [OH-] = 0,01778 mol/dm³

    [NaOH] = [OH-] = 0,01778M

    :•)
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