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21 July, 17:08

You wish to prepare 220 grams of 21.2 % FeCl,.

You will need

grams of iron (II) chloride

mL of water.

and

Assume that the density of water is 1.00 g/ml

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Answers (1)
  1. 21 July, 17:14
    0
    You will need 46.6 grams of iron (II) chloride and 173 mL of water.

    Explanation:

    x = mass of FeCl₂, y = mass of water

    Assuming the percentage is by weight, we can write two equations:

    x / (x + y) = 0.212

    x + y = 220

    Solving the system of equations:

    x / 220 = 0.212

    x ≈ 46.6

    y ≈ 173

    You will need 46.6 grams of iron (II) chloride and 173 mL of water.
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