Calculate the mass of silver chloride in grams required to make 5.8 g of silver plating.

Question

Sammy Coleman

Chemistry

31 January, 05:01

Calculate the mass of silver chloride in grams required to make 5.8 g of silver plating.

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Zion Ritter · Answer 1

Silver chloride is simply AgCl while silver is Ag so we see that there is one mole to one mole correspondence. First calculate the moles of Ag:

moles Ag = 5.8 g / (107.87 g/mol)

moles Ag = 0.0538 mol

Then the mass of AgCl required:

mass AgCl = 0.0538 mol * 143.32 g/mol

mass AgCl = 7.71 grams