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20 November, 19:20

Determine the percentage composition (by mass) of oxygen in NH4NO3.

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  1. 20 November, 19:30
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    60%

    Explanation:

    M (NH4NO3) = 2*14 + 4*1 + 3*16 = 80 g/mol

    M (3O) = 3*16 = 48 g/mol

    (48/80) * 100 % = 60% oxygen by mass.
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