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13 April, 02:44

What mass of silver ag which has an atomic mass of 107.87 amu contains the same number of atoms contained in 10.0g of boron b which has an atomic mass of 10.81 amu?

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  1. 13 April, 02:47
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    To contain the same number of atoms also mean to contain the same number of moles. So let us say that X is the mass of Silver Ag required, so that:

    X / 107.87 = 10 / 10.81

    X = 99.79 g
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