A mixture with H2 and He exerts a total pressure of 0.48 atm. If there is 1.0 g of H2 and 1.0 g of He in the mixture, what is the partial pressure of the helium gas?

Question

Luciana Berry

Chemistry

25 September, 02:02

A mixture with H2 and He exerts a total pressure of 0.48 atm. If there is 1.0 g of H2 and 1.0 g of He in the mixture, what is the partial pressure of the helium gas?

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Alexa Yoder · Answer 1

Answer is: the partial pressure of the helium gas is 0.158 atm.

p (mixture) = 0.48 atm; total pressure.

m (H₂) = 1.0 g; mass of hydrogen gas.

n (H₂) = m (H₂) : M (H₂).

n (H₂) = 1.0 g : 2 g/mol.

n (H₂) = 0.5 mol; amount of hydrogen.

m (He) = 1.0 g; mass of helium.

n (He) = 1 g : 4 g/mol.

n (He) = 0.25 mol; amount of helium.

χ (H₂) = 0.5 mol : 0.75 mol.

χ (H₂) = 0.67; mole fraction of hydrogen.

χ (He) = 0.25 mol : 0.75 mol.

χ (He) = 0.33; mole fraction of helium.

p (He) = 0.33 · 0.48 atm.

p (He) = 0.158 atm; the partial pressure of the helium gas.