A gas occupies 900.0 ML at temperatures of 27.0 Celsius. What is the volume at 123.0 celsius

1188.0 mL.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have two different values of V and T:

V₁T₂ = V₂T₁

V₁ = 900 mL, T₁ = 27.0°C + 273 = 300.0 K.

V₂ = ? mL, T₂ = 123.0°C + 273 = 396.0 K.

∴ V₂ = V₁T₂/T₁ = (900 mL) (396 K) / (300.0 K) = 1188.0 mL.

1188 ml