Suppose we have a 12.2litre sample containing 0.50M of oxygen at 25°c. If all of this oxygen (o2) is converted to ozone at the same temperature and pressure. What will be the volume of ozone?

V2 = 8.2 L

Explanation:

Given dа ta:

Molarity of oxygen = 0.50 M

Volume = 12.2 L

Volume of ozone = ?

Solution:

Number of moles of oxygen = molarity * volume

Number of moles = 0.50 M * 12.2 L

Number of moles = 6.1 mol

Chemical equation:

3O₂ → 2O₃

Moler ratio:

O₂ : O₃

3 : 2

6.1 : 2/3*6.1 = 4.1 mol

According to Avogadro law:

V1/n1 = V2/n2

V2 = V1n2/n1

V2 = 12.2 L * 4.1 mol / 6.1 mol

V2 = 50.02 L. mol / 6.1 mol

V2 = 8.2 L