Determine the molecular mass ratio of two gases whose rates of effusion have a ratio of 16 : 1.

Question

Brendon Briggs

Chemistry

14 August, 17:10

Determine the molecular mass ratio of two gases whose rates of effusion have a ratio of 16 : 1.

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Skye Barron · Answer 1

Answer is: the molecular mass ratio of two gases is 1 : 256.

rate of effusion of gas1 : rate of effusion of gas = 16 : 1.

rate of effusion of gas1 = 1/√M (gas1).

rate of effusion of gas2 = 1/√M (gas2).

rate of effusion of gas1 = rate of effusion of gas2 · 16.

1/√M (gas1) = 1/√M (gas2) · 16 / ².

1/M (gas1) = 1/M (gas2) · 256.

M (gas1) · 256 = M (gas2).