Ask Question
4 October, 22:26

Given the balanced equation:

Fe (s) + CuSO4 (aq) FeSO4 (aq) + Cu (s)

What total mass of iron is necessary to produce 1.00 mole of copper?

A) 26.0 g

B) 55.8 g

C) 112 g

D) 192 g

+2
Answers (1)
  1. 4 October, 22:29
    0
    B.) Since the mole ratio is 1:1. For every mole of copper, you have one mole of iron. To produce 1.00 mole of copper, you need 1.00 mole of iron. A mole of iron is equivalent to 55.85 grams.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Given the balanced equation: Fe (s) + CuSO4 (aq) FeSO4 (aq) + Cu (s) What total mass of iron is necessary to produce 1.00 mole of copper? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers