If a 53.27g sample of potassium nitrate (KNO3) is dissolved in enough water to make 461 mL of solution, what will be the molarity?

Question

Mina Frost

Chemistry

28 December, 22:10

If a 53.27g sample of potassium nitrate (KNO3) is dissolved in enough water to make 461 mL of solution, what will be the molarity?

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Elisa · Answer 1

1.143 M.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute) / (V of the solution (L)).

∴ M = (mass/molar mass) of KNO₃ / (V of the solution (L)).

∴ M = (mass/molar mass) of KNO₃ / (V of the solution (L)) = (53.27 g / 101.1 g/mol) / (0.461 L) = 1.143 M.