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20 November, 23:50

Determine the number of atoms and the mass of zirconium, silicon and oxygen found in 0.3384 Mol of zircon ZrSiO4, a

semiprecious Stone.

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  1. 20 November, 23:56
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    1 mol of ZrSiO₄, have, 1 mol of Zr, 1 mol of Si and 4 mol of Oxygen.

    since,

    1 mol of a substance have 6.022 * 10 ²³ particles,

    From the question,

    0.3384 mol of zircon ZrSiO₄,

    hence,

    from the above equation,

    1 mol of a substance have 6.022 * 10 ²³ particles,

    0.3384 mol = 0.3384 * 6.022 * 10 ²³ number of atoms

    = 2.037 * 10 ²³ number of atoms

    Hence,

    0.3384 mol of ZrSiO₄ will have, 0.3384 mol of Zr, 0.3384 mol of Si and 4*0.3384 mol of Oxygen.

    Hence,

    number of atoms of Zr = 0.3384 mol * 6.022 * 10 ²³ = 2.037 * 10 ²³ number of atoms number of atoms of Si = 0.3384 mol * 6.022 * 10 ²³ = 2.037 * 10 ²³ number of atoms number of atoms of O = 4 * 0.3384 mol * 6.022 * 10 ²³ = 8.148 * 10 ²³ number of atoms

    The mass is calculated as -

    since,

    Moles is denoted by given mass divided by the molecular mass,

    Hence,

    n = w / m

    n = moles,

    w = given mass,

    m = molecular mass.

    n = w / m

    w = n * m

    mass of Zr,

    Since we know, the molecular mass of Zr = 91 g/mol

    moles of Zr = 0.3384 mol

    using the above formula,

    w = n * m

    w = 0.3384 mol * 91 g/mol = 30.79 g

    hence,

    The mass of Zr = 30.79 g

    mass of Si,

    Since we know, the molecular mass of Si = 28 g/mol

    moles of Si = 0.3384 mol

    using the above formula,

    w = n * m

    w = 0.3384 mol * 28 g/mol = 9.475 g

    hence,

    The mass of Si = 9.475 g

    mass of O,

    Since we know, the molecular mass of O = 16 g/mol

    moles of Si = 1.3536 mol

    using the above formula,

    w = n * m

    w = 1.3536 mol * 16 g/mol = 21.65 g

    hence,

    The mass of O = 21.65 g
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