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1 February, 12:01

The mass of an electron is 9.11 * 10-31 kg. What is the uncertainty in the position of an electron moving at 2.00 * 106 m/s with an uncertainty of Δv = 0.01 * 106 m/s?

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  1. 1 February, 14:01
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    Given The mass of an electron is 9.11 * 10-31 kg

    position of an electron moving at 2.00 * 106 m/s with an uncertainty of Δv = 0.01 * 106 m/s

    Therefore, in our case we know the value for Δv but want to calculate Δx. Let's change the equation to an equality

    Δx = h/Δp

    Since we know momentum p = mv then

    Δx = 6.626 * 10^-34 / m * Δv

    Δx = 6.626 * 10^-34 / 9.109 * 10-31 * 1.00 * 10^4

    Δx = 7.274 * 10^-8 m
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