The volume of an air bubble at the bottom of a lake is 1.35 mL. If the pressure at the bottom of the lake is 125 kPa and the air pressure at the top of the lake is 105 kPa, what will the volume of the bubble be when it rises to the surface?

1.61 mL

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 1.35 mL

Initial pressure (P1) = 125 kPa

Final pressure (P2) = 105 kPa

Final volume (V2) = ... ?

Step 2:

Determination of the volume of the air bubble at the surface of the lake.

This can be obtained by use the Boyle's law equation as follow:

P1V1 = P2V2

125 x 1.35 = 105 x V2

Divide both side by 105

V2 = (125 x 1.35) / 105

V2 = 1.61 mL

Therefore, the volume of the air bubble at the surface of the lake is 1.61 mL